By Javier Jiménez
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30 kN FU > FD It will float. 2740 kN = 274 N; because w = 277 N > Fb—It will sink. 14 From Prob. 9 lb/ft > γw - cube would tend to float. 81 kN/m —it would float. 8836 m3 Entire hemisphere is submerged. 082 m) ( ) Wt. 30 From Prob. 6875 ft3 ends Vol. 196 ft3 sub. 34 4 Drums Weigh 4(30 lb) = 120 lb Wt. of platform and load = 1801 − 120 = 1681 lb See Prob. 63 for method of computing AS. wdrums + wwood + wload − FbD − Fbw = 0 wdrums = 4(30 lb) = 120 lb (Prob. 5 lb (Prob. 32) FbD = 1801 lb (Prob. 6 lb (Prob.
26. 46 3 1728 in 3 ft See Prob. 28. 97 in [See Prob. 389 m2 FH = 0 because horiz. 50) FV = 17328 lb = FR FH = 0 because horiz. 55 (See Prob. 99) Eq. 00 FH (See Prob. 65 kN/ m 2 Eq. 11, net vertical force equals the weight of the displaced fluid acting upward and the weight of the cylinder acting downward. 58 See Prob. 57. 59 See Prob. 57. 28 lb up But this indicates that the cylinder would float, as expected. Then, the force exerted by the cylinder on the bottom of the tank is zero. 60 The specific weight of the cylinder must be less than or equal to that of the fluid if no force is to be exerted on the tank bottom.
An introduction to turbulence by Javier Jiménez